Given: Circle O with diameter AB, arc AM = arc DM
Prove: △AMB ≅ △CMB
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∠AMB = 90
△AMB ≅ △CMB
ASA (Angle-Side-Angle)
arc AB = 180
Circle O with diameter AB, arc AM = arc DM
Substitution
The angles in a linear pair are supplementary
Inscribed angle measures half its intercepted arc
Given
∠ABM = ∠CBM
∠ABM = (1/2) * arc AM and ∠CBM = (1/2) * arc DM
Reflexive
Substitution
Inscribed angle measures half its intercepted arc
∠CMB = 90
MB = MB
∠AMB = (1/2) * arc AB
Definition